(7x^2-4x+2)=(3x^2-6x-5)

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Solution for (7x^2-4x+2)=(3x^2-6x-5) equation: 



(7x^2-4x+2)=(3x^2-6x-5)

We move all terms to the left:

(7x^2-4x+2)-((3x^2-6x-5))=0

We get rid of parentheses

7x^2-4x-((3x^2-6x-5))+2=0



We calculate terms in parentheses: -((3x^2-6x-5)), so:

(3x^2-6x-5)

We get rid of parentheses

3x^2-6x-5

Back to the equation:

-(3x^2-6x-5)



We get rid of parentheses

7x^2-3x^2-4x+6x+5+2=0

We add all the numbers together, and all the variables

4x^2+2x+7=0

a = 4; b = 2; c = +7;
Δ = b2-4ac
Δ = 22-4·4·7
Δ = -108
Delta is less than zero, so there is no solution for the equation

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